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Browse: Home / LEARNING / Maths

Train A and Train B math problem?

Melissa Brinkley: Train A and Train B math problem?
Train A and B are traveliong in the same direction on parallel tracks. Track A is traveling at 40 mph B is going 48 mph. If train A passes the station at 525pm and train b passes the same station at 540 what time will train B catch up to train A?

Answers and Views:

Answer by como
Train A________Train B
40 mph________48 mph
5 : 25__________5 : 40

In 15 mins train A travels 10 miles

Relative speed of trains is 8 mph

Time for train B to travel 10 miles is given by :-
10/8h = 5/4h = 1h 15min

Answer by StevenC
I’m going to let h be the number of hours it takes train B to catch up to train A.

so when train B passes the station, train A has already been traveling 15 minutes (1/4 hour)

distance train A has traveled = (h+1/4)hours * 40 miles per hour = (40h + 10) miles

distance train B has traveled = h hours * 48 miles per hour = (48h) miles

these distances are the same (otherwise train B won’t have “caught up”), so

40h + 10 = 48h

solve for h

10 = 8h <– subtract 40h from both sides

5/4 = h <– divide both sides by 8 and reduce

so the time it takes train B to catch up is 1 hour, 15 minutes.

So…. add 1 hour 15 minutes to the time train B passed the station and it will be

6:55pm

Answer by shazam!
t=5:40 – 5:25
t = 15″
r = 48mph-40mph
r = 8 mph
8mph = 480″
480″/15″ = 32″
32″ + 5:25 = 5:57

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