maths…..?

iluvanswers: maths…..?
Find a number LESS than fifty that has a REMAINDER of one when divided by 2, 3 or 4. But if divided by 5 there is no remainder

What is the number?

It took me a quite a while to work it out but i eventually got it in the end…

This question was in a year8/grade 8 school maths test paper

Just wanna c wat u guyz come up wif…

Pls leave ur answers as answers

Thanks…

Answers and Views:

Answer by Jimmy
25
the fact that there is no remainder dividing by 5 quickly narrows the possible numbers down to 5, 10, 15, 20, 25, 30, 35, 40, and 45.

Answer by DaveM
If a number has remainder 1 when divided by 2,3,4, then it has a remainder of 1 when divided by lcm(2,3,4) = 12.

Therefore, the number is of the form 12k+1.

This narrows it down to
1, 13, 25, 37, 49

The only one divisible by 5 is 25.

Therefore, the answer is 25.

Answer by hd_kwan
25, piece of cake…
2*3*4=24
24+1=25
done

Answer by Lisa T
Well if it’s less than 50 and divisible by 5 your only options are
5,10,15,20,25,30,35,40,45
Now if when divided by 2 it has a remainder of 1 that eliminates all of the even numbers so now the list is
5,15,25,35,45
it cannot be divisible by 3 so the list is
5,25,35
25 is the only one that has a remainder of 1 when divided by 2, 3, or 4

Answer by michaelempeigne
2*3*4 = 24
24+1 = 25

check 25/2 =- 12 remainder 1
25/3 = 8 remainder 1
25/4 = 6 remainder 1
25/5 = 5 no remainder

Answer by Madhukar Daftary
LCM of 2, 3, 4 is 12
The required number must be a multiple of LCM + 1
Multiples of LCM + 1 less than 50 are
13, 25, 37, 49
Of these, only 25 is divisible by 5
=> 25 is the answer.

Answer by Mitch Royal
25.

(in Singapore, an 8-year-old is able to answer!)