If train A and train B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mph?

john: If train A and train B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mph?
and train B is traveling at 100 mph. Train A passes the station at 1:10 am. If train B passes the station at 1:22 am what time will train B catch up to train A

Answers and Views:

Answer by David P
It doesn’t matter, you are only riding one of them.

Answer by Virgop t
Train B will catch train A at 2:10. Reason as follows

since train B passes station after 12 minutes = 12/60 = 1/5 hr. Hence with its current speed of 100 mph it has to travel 100mphr * 1/5 hr = 20 additional miles before it reaches station.

Lets Assume that both trains meet at a distance ‘x’ from the station. This means both the trains will take the same time (from their initial position – train A at station and train B still far away) to reach the distance ‘x’. lets say that parameter is ‘t’. Hence for train A : t=x/80.
Similarly for train B: t=(x+20)/100. Now we equate both of these

x/80 = (x+20)/100

solving this we get x=80. Hence from Train A’s equation (you can plug value of ‘x’ in train B’s eq too) time t=x/80=80/80=1 hr. Counting that for train A 1:10 am + 1 hr = 2:10 am.

~ A wise East Indian – now a computer engineer – We solved these problems in 5th – 6th grade Math in India….lol

Answer by … ‹(•¿•)› …
Train B will catch up at approximately the same time that you should be starting your math class.

Go back to school, and stop waiting for people to do your homework for you.