mslayd02: I need help with this word problem did 5 times got 5 different answers?
Train A and train B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 110 miles per hour. Train A passes a station at 8:25 AM. If train B passes the same station at 8:37 AM, at what time will train B catch to train A?
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Answer by Articuno
You can obtain the following from the passage:
– Train B is 10mph faster than Train A.
– Train A got a 12-minute head start.
Instead of saying that B is 10mph faster than A, you could also say B is 1/6 miles per minute faster than A. (You just divide by 60 to convert hour to minute.) Meaning that each minute, B gains on A by 1/6 of a mile.
Train A got a 12-minute head start. That means it’s already 100 * (12/60) miles ahead, or 20 miles ahead. Since B gains on A by 1/6 of a mile every minute, it will take 20/(1/6) minutes to reach A. That’s 120 minutes, or two hours. Add 2 hours to the time.
Answer: 10:37 am
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