can someone help me with this math problem?? its one of those train A and train B problems?

quazie621: can someone help me with this math problem?? its one of those train A and train B problems?
train A and B are traveling in the same direction on parallel tracks. train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. train A passes a station at 9:25 P.M. If train B passes the same station at 9:55 P.M, at what time will train B catch up to train A?

Answers and Views:

Answer by kim t
x hour after 9:25PM

40x = 48(x – 0.5)—->x = 3 or at 0:25 AM

Answer by Independent_guy
12:25am.
explanation: in 30 minutes train is 20 miles ahead. to catch the train the train needs to travel 20 miles at a relative pace of 8 miles per hour. takes 2.5 hours!

Answer by jit
9:55 + (40*0.5)/(48-40)
= 9:55+2:30
= 12:25 i.e. 0:25AM next day

Answer by bskelkar
I have not used miles in ages. But I shall try.
B is 30 min behind A is very clear and 8mph faster.
and A is 20 miles ahead of B.
So it will pass train A in 20/8 hours or 2 hours and 30 minutes.
BTW in which part of the world do you use mile even in these days. It was discarded in around 1965

Answer by Pelican
Tell your math teacher “Trains are never on time. “

Answer by Oceanside
difference between the time they pass the station is 30 mins, which is 1/2 hour or 0.5 hrs

let x be the time it takes train A to meet train B

40 x = 48( x ) – 0.5
0.5 = 48 x – 40 x
8 x = 0.5
x = 1 / 16

1 / 16 * 60mins = 3.75 mins

9.55pm —3.75mins–>9.58pm

I’m not very sure if it’s right..I haven’t done this in a long time..hope it was of some help though..