ALGEBRA????????????????????????

Cyrus: ALGEBRA????????????????????????
how do you find out this problem (it would help if you teach me step by step)

What is the solution to the equation 1/5(10x+30)=6x+7

Answers and Views:

Answer by JOS J
1/5(10x+30)=6x+7

x = -1/4

Answer by a_nobody
1/5(10x+30)=6x+7
1/5 * 10/1 = 2
1/5 * 30/1 = 6
you can put any whole # over 1 to make it a convenient fraction
2x + 6 = 6x + 7
collect like terms
4x = -1
x = – 1/4

Answer by Advisor 6
First of all, distribute the left side

1/5 * 10x + 30 * 1/5 = 6x+7
2x + 6 = 6x+7

Move the x to one side, the constants to the other
-1 = 4x

Divide both sides by 4.

x = -1/4

Answer by electron1
What is the solution to the equation 1/5(10x+30)=6x+7

If 1/5 is multiplied times (10 x + 30):
1/5 * (10 x + 30) = 6x + 7
Multiply both sides by 5, to remove the fraction
(10 x + 30) = 5 * (6x + 7)
10 x + 30 = 30x + 35

Subtract (10x + 30) from both sides
0 = 30x + 35 – (10x + 30) = 20x + 5
20 x = -5
x = -1/4

Answer by Steven
1/5(10x+30)=6x+7

multiply both sides by 5
(10x+30)=30x+35

subtract 10x from both sides
[keeps the variable positive]
subtract 35 from both sides

-5=20x
x= -5/20

x= -1/4

Answer by osnapitzangie
heres the steps
1/5(10x+30)=6x+7
2x+6=6x+7
6=4x+7
-1=4x
x= -1/4

Answer by BisexualGirlx
10x +30 = 30x + 35
30=20x+35
20x= -5
x= -5/20
x= -1/4

Answer by Tango Charlie
x = -1/4