please help?

lulu: please help?
how do i solve this if a speed of train A is 8 mph slower then the speed of train B and train A travels 190 miles in the same time it takes train B to travel at 230 miles what is the speed for train a and train B? just need to know how to solve this them ill do the rest of my work myself thank you

Answers and Views:

Answer by Rebecca L
Use the following equations:
speed of A = speed of B – 8
distance = speed * time
time = distance/speed

This gives us (where v is speed):
va = vb – 8 (equation 1)

time(a)=time(b)
distance(a)/speed(a)=distance(b)/speed(b)
190 / va = 230 / vb (equation 2)

Solve the two equations for va and vb.

Answer by ultimate reality1
You want to set up 2 equations and equate them. The main equation you’ll have to use is v = d/t

Now rewrite it like this: t = d/v

Why? Because the problem gives you a hint there when it says that train A travels so and so in the “same time” it takes train B to travel so and so.

t=t
So d/va for A = d/vb for B
which is 190/va = 230/vb

where now you just use the constraint given to reduce the 2 equations into 1 big equation with 1 unknown. That constraint is that train A is 8mph slower than train B

va = vb – 8

Plug it into the equation above and solve for vb. And once you have vb, just subtract 8 from it to get va.

Answer by Groundhog#1
B m/h = A m/h + 8 m/h…

230-190 = How many miles during “T” (time) B traveled further

That # (40)/8 = “T” in hours.

A/ “T” in hours = Answer A in mph
B/ “T” in hours = Answer B in mph