buffalo: Find the speed of train A and train B?
Speed of train A is 10 mph slower than the speed of train B. Train A travels 220 miles in the same time it takes train B to travel 270 miles. Find the speed of each train?
Answers and Views:
Answer by Olly B
A=speed of train A
B=speed of train B
1) A=B-10
2) 220A=270B
22A=27B
A=27/22B
2 in 1
27/22B=B-10
10=B-27/22B
10=B(1-27/22)
B=10/(1-27/22)
B=-9.773
A=-9.773 -10
A=.277
A=
v=s/t
t=s/v
vA=vB-10
sA=220
sB=270
tA=tB
220 / (vB-10) = 270 / vB
220 vB = 270(vB-10)
vB=54
vA=44
1. Sa = Sb – 10
2. 220/Sa = 270/Sb
now solve:
220Sb = 270Sa
220Sb = 270 * (Sb – 10)
220Sb = 270Sb – 2700
50Sb = 2700
Sb = 2700/50 = 54 miles per hour.
Sa = 54-10 = 44 miles per hour
Answer by PeedlepupThis is a mathematics “word” problem, and it belongs in the “HOMEWORK HELP” section. Just because it contains the word “train” does not make it a question for the “Rail” sub-section.Answer by Rango
wow
that is awfully complicated
luckily I am the engineer on the slow train and dont have to do complicated mathAnswer by Fred M
try the math or homework categories….
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